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假使要利用Eclipse功能實做Adapter可以利用以下程式碼

首先先定義Object User extends PlatformObject (或是implment IAdaptable,但是架構上會有些許不同)

public class User extends PlatformObject { private String name; private String age; private boolean isMale; }

實做class UserProgressAdapterFactory implements IAdapterFactory

public class UserProgressAdapterFactory implements IAdapterFactory { private static final Class[] types = { Map.class }; @Override public Object getAdapter(Object adaptableObject, Class adapterType) { if (adaptableObject instanceof User && adapterType == Map.class) { Map<String, String> temp = new HashMap<String, String>(); User user = (User) adaptableObject; temp.put("userName", user.getName()); temp.put("userAge", user.getAge()); temp.put("userSex", user.isMale() ? "Male" : "Female"); return temp; } return null; } @Override public Class[] getAdapterList() { // TODO Auto-generated method stub return types; } }

最後在 Activator 註冊UserProgressAdapterFactory 提供給User.class使用

public void start(BundleContext context) throws Exception { super.start(context); plugin = this; IAdapterManager m = Platform.getAdapterManager(); IAdapterFactory f = new UserProgressAdapterFactory(); m.registerAdapters(f, User.class); }

最後結果測試

User user=new User("CSLin","18",true);
System.out.println(user.getAdapter(Map.class));====>{userSex=Male, userName=CSLin, userAge=18}

我門可以在User定義toMap()來產生map或者是直接呼叫getAdapter的功能來產生map,不過似乎利用getAdapter不支援泛型

public Map<String,String> toMap(){ return (Map<String,String>)getAdapter(Map.class); }